(x^2-4x+5)/(x-2)

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Solution for (x^2-4x+5)/(x-2) equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(x^2-(4*x)+5)/(x-2) = 0

(x^2-4*x+5)/(x-2) = 0

x^2-4*x+5 = 0

x^2-4*x+5 = 0

DELTA = (-4)^2-(1*4*5)

DELTA = -4

DELTA < 0

1 = 0

1/(x-2) = 0

x belongs to the empty set

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